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21 March, 06:08

A car slows down from - 27.7 m/s to - 10.9 m/s while undergoing a displacement of - 105 m. what was it's acceleration?

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  1. 21 March, 08:06
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    a = 3.088 m/s²

    Step-by-step explanation:

    u = - 27.7 m/s

    v = - 10.9 m/s

    s = - 105 m

    By using the formula, s = 1/2 (u + v) t

    -105 = 1/2 (-27.7-10.9) t

    -105 = 1/2 (-38.6) t

    -105 = - 19.3t

    -105/-19.3 = t

    t = 5.44s

    a = (v - u) / t

    a = (-10.9 - (-27.7)) / 5.44

    a = 16.8/5.44

    a = 3.088 m/s²
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