A car slows down from - 27.7 m/s to - 10.9 m/s while undergoing a displacement of - 105 m. what was it's acceleration?

a = 3.088 m/s²

Step-by-step explanation:

u = - 27.7 m/s

v = - 10.9 m/s

s = - 105 m

By using the formula, s = 1/2 (u + v) t

-105 = 1/2 (-27.7-10.9) t

-105 = 1/2 (-38.6) t

-105 = - 19.3t

-105/-19.3 = t

t = 5.44s

a = (v - u) / t

a = (-10.9 - (-27.7)) / 5.44

a = 16.8/5.44

a = 3.088 m/s²