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12 December, 01:10

There are 7 cherries and 3 grapes in a bag. What is the pobability of selecting 2 grapes at random without replacement?

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  1. 12 December, 01:36
    0
    1/15

    Step-by-step explanation:

    7+3 = 10 items in the bag

    P (grape) = grapes/total

    3/10

    No replacement

    7 cherries 2 grapes = 9 items

    P (grape) = grapes/total

    2/9

    P (grape, no replacement, grape) = 3/10*2/9

    =1/15
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