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11 December, 15:42

A ball is thrown straight up from the top of a building that is 400 ft high with an initial velocity of 64 ft/s. The height of the object can be modeled by the equation s (t) = - 16t2 + 64t + 400. Determine the time (s) the ball is higher than the building. Write your answer in interval notation. Then in two or more complete sentence, explain your solution method.

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  1. 11 December, 18:21
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    The time (s) the ball is higher than the building: Interval (0,4)

    Step-by-step explanation:

    s (t) = -16t^2+64t+400

    Determine the time (s) the ball is higher than the building:

    s (t) >400

    -16t^2+64t+400>400

    Subtracting 400 both sides on the inequality:

    -16t^2+64t+400-400>400-400

    -16t^2+64t>0

    Multiplying the inequality by - 1:

    (-1) (-16t^2+64t>0)

    16t^2-64t<0

    Fatorizing: Comon factor 16t:

    16t (16t^2/16t-64t/16t) <0

    16t (t-4) <0

    t is greater than zero:

    t>0→t-4<0→t-4+4<0+4→t<4

    Then t>0 ant t<4:

    Solution = (0, Infinite) ∩ (-Infinite, 4)

    Solution = (0,4)
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