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12 July, 11:08

Given f (x) = 6x^4 - 10x^3 + 40x - 50, find f (2)

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  1. 12 July, 11:55
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    F (x) = 6x^4-10x^3+40x-50, plug 2 in for x

    f (2) = 6 (2) ^4-10 (3) ^3+40 (2) - 50

    f (2) = 12^4-30^3+80-50

    f (2) = 20735-27,000+80-50

    f (2) = -6,235
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