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Mathematics
Amelie Luna
22 February, 00:56
Hence solve the equation x^3+x^2-6x=0
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Kyler Dean
22 February, 01:11
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Answer:x³ + x² - 6x = 0
x (x² + x - 6) = 0
x (x² + 3x - 2x - 6) = 0
x[x (x + 3) - 2 (x + 3) ] = 0
x (x - 2) (x + 3) = 0
x₁ = 0
x - 2 = 0 = > x₂ = 2
x + 3 = 0 = > x₃ = - 3
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Sasha Smith
22 February, 02:22
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x³ + x² - 6x = 0
x (x² + x - 6) = 0
x (x² + 3x - 2x - 6) = 0
x[x (x + 3) - 2 (x + 3) ] = 0
x (x - 2) (x + 3) = 0
x₁ = 0
x - 2 = 0 = > x₂ = 2
x + 3 = 0 = > x₃ = - 3
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