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12 July, 07:47

What is a cubic polynomial function in standard form with zeros 1 - 2 and 2?

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  1. 12 July, 11:18
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    f (x) = x³ - x² - 4x + 4

    Step-by-step explanation:

    Given the zeros of a polynomial say x = a, x = b, x = c then

    (x - a), (x - b), (x - c) are the factors of the polynomial and

    f (x) is the product of the factors

    here x = 1, x = - 2, x = 2, hence

    (x - 1), (x + 2), (x - 2) are the factors and

    f (x) = a (x - 1) (x + 2) (x - 2) ← a is a multiplier

    let a = 1 and expand the factors

    f (x) = (x - 1) (x² - 4)

    = x³ - 4x - x² + 4

    = x³ - x² - 4x + 4 ← in standard form
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