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13 April, 18:04

The probability is 0.36 that the amount spent on a randomly selected child will be between what two value equidistant from the mean?

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  1. 13 April, 19:25
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    Assuming a standard normal distribution, the positive value of interest will be that corresponding to the 50 + 36/2 = 68th percentile. A suitable probability calculator will give that value as 0.46770.

    The values that are within ±0.46770 standard deviations from the mean will have a probability of 0.36.
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