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1 June, 10:47

A rocket is launched vertically from the ground with an initial velocity of 56 ft/sec

(a) Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched.

(b) Graph on the coordinate plane.

(c) Use your graph from Part 3 (b) to determine the rocket's maximum height, the amount of time it took to reach its maximum height, and the amount of time it was in the air.

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  1. 1 June, 14:08
    0
    y = 17x - 4.5x²

    height = 16m at 2 sec

    total time = 3.77 sec

    Step-by-step explanation:

    Given the initial velocity of rocket = 56ft/sec

    We use newton formula

    s = ut + 1/2at²where s = distance

    u = initial velocity

    t = time

    a = acceleration due to gravity = 9.8m/s²

    since the rocket is launched upward, it is against the gravity so a = - 9.81.

    56 feet = 17.0688 = 17

    suppose s = height = y and time = x

    y = 17x - 1/2 (9.81) x²

    or

    y = 17x - 4.5x²

    b)

    as x can not be negative so domain will be from 0 to 3.78

    put value of x to find value of y and then plot these on graph

    This graphs will be a parabola which opens downward.

    c)

    at 2 sec, y value is greatest = 16 meters

    time for which rocket was in the air = 3.77sec
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