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6 April, 19:44

Solve y-2x=1, 3x-4y=1 using substitution m

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Answers (2)
  1. 6 April, 19:57
    0
    y-2x=1

    3x-4y=1

    y=1+2x

    3x-4y=1

    y=1+2x

    3x-4 (1+2x) = 1

    y=1+2x

    3x-4-8x=1

    y=1+2x

    -5x-4=1

    y=1+2x

    -5x=1+4

    y=1+2x

    -5x=5

    y=1+2x

    x=-1

    y=1+2 * (-1)

    x=-1

    y=1 + (-2)

    x=-1

    y=-1

    x=-1
  2. 6 April, 20:34
    0
    Step-by-step explanation:

    given

    y - 2x = 1

    y = 1 + 2x ... equation 1

    3x - 4y = 1 ... equation 2

    Now putting y = 1 + 2x in equation 2

    3x - 4 (1 + 2x) = 1

    3x - 4 - 8x = 1

    - 5x = 1 + 4

    - 5x = 5

    Therefore x = - 1

    Now putting x = - 1 in equation 1

    y = 1 + 2 * (-1)

    = 1 - 2

    = - 1
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