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9 February, 10:19

A, B, C are positive integers such that A:B = 7:9 and B:C = 12:7, what is the smallest possible value of A?

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  1. 9 February, 13:11
    0
    28

    Step-by-step explanation:

    A/B = 7x/9x

    B/C = 12y/7y

    9x=12y

    x=12/9=4/3y

    7x = 7 * (4/3) * y = 7 * (4/3) = 28/3 - not an integer

    7 * (4/3) * 2 = 56/3 - not an integer

    7 * (4/3) * 3 = 28
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