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10 June, 10:46

Solve for y:

Y^2-2xy=1

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  1. 10 June, 12:28
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    y = x ±√ (x²+1)

    Step-by-step explanation:

    Rewrite to standard quadratic form, then use the quadratic formula.

    ... y² - 2xy - 1 = 0

    ... a=1, b=-2x, c=-1, so the quadratic formula

    ... y = (-b ±√ (b²-4ac)) / (2a)

    can be filled in as ...

    ... y = - (-2x) ±√ ((-2x) ² - 4 (1) (-1))) / 2 (1))

    ... y = x ±√ (x² + 1)

    For any given value of x, there are two possible values of y. This is not a function.
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