10 June, 10:46
Solve for y:
10 June, 12:28
y = x ±√ (x²+1)
Rewrite to standard quadratic form, then use the quadratic formula.
... y² - 2xy - 1 = 0
... a=1, b=-2x, c=-1, so the quadratic formula
... y = (-b ±√ (b²-4ac)) / (2a)
can be filled in as ...
... y = - (-2x) ±√ ((-2x) ² - 4 (1) (-1))) / 2 (1))
... y = x ±√ (x² + 1)
For any given value of x, there are two possible values of y. This is not a function.
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» Solve for y: Y^2-2xy=1