If the domain of f (x) = 4 + x2 is {-1, 0, 1, 2}, what is the range?

Answer: y = {5, 4, 8}

Step-by-step explanation:

f (x) = 4 + x²

f (-1) = 4 + (-1) ²

= 4 + 1

= 5

f (0) = 4 + (0) ²

= 4 + 0

= 4

f (1) = 4 + (1) ²

= 4 + 1

= 5

f (2) = 4 + (2) ²

= 4 + 4

= 8

Put the values from domain to the equation of the function.

f (x) = 4 + x²

f (-1) = 4 + (-1) ² = 4 + 1 = 5

f (0) = 4 + 0² = 4 + 0 = 4

f (1) = 4 + 1² = 4 + 1 = 5

f (2) = 4 + 2² = 4 + 4 = 8

Answer: The range = {4, 5, 8}