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17 February, 00:08

If the domain of f (x) = 4 + x2 is {-1, 0, 1, 2}, what is the range?

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Answers (2)
  1. 17 February, 01:53
    0
    Answer: y = {5, 4, 8}

    Step-by-step explanation:

    f (x) = 4 + x²

    f (-1) = 4 + (-1) ²

    = 4 + 1

    = 5

    f (0) = 4 + (0) ²

    = 4 + 0

    = 4

    f (1) = 4 + (1) ²

    = 4 + 1

    = 5

    f (2) = 4 + (2) ²

    = 4 + 4

    = 8
  2. 17 February, 03:58
    0
    Put the values from domain to the equation of the function.

    f (x) = 4 + x²

    f (-1) = 4 + (-1) ² = 4 + 1 = 5

    f (0) = 4 + 0² = 4 + 0 = 4

    f (1) = 4 + 1² = 4 + 1 = 5

    f (2) = 4 + 2² = 4 + 4 = 8

    Answer: The range = {4, 5, 8}
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