Find the volume of a right circular cone that has a height of 9.9 in and a base with a

diameter of 10.1 in. Round your answer to the nearest tenth of a cubic inch.

Answer:

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volume ≈ 264.3 inches³ (nearest tenth)

Step-by-step explanation:

volume of a cone = 1/3πr²h

where

h = height

r = radius

h = 9.9 inches

r = 10.1/2 = 5.05 inches

volume of a cone = 1/3πr²h

volume = 1/3 * π * 5.05² * 9.9

volume = 1/3 * π * 25.5025 * 9.9

volume = 1/3 * π * 252.47475

volume = 84.15825π

volume = 264.256905

volume ≈ 264.3 inches³ (nearest tenth)