Use the substitution method to solve these simultaneous equations.

a) 3x + 2y = 33

y = 41 - 5x

b) y = 3x - 3

-5x + 3y = 3

c) 4x + y = 9

y = 11 - 5x

d) x = - 5 - 2y

5y + x = - 11

e) y = 2x + 1

-5x - 4y = 35

as

Step-by-step explanation:

nswer:

Step-by-step explanation:

a) 3x+2 (41-5x) = 33 as y=41-5x is given

3x+82-10x=33

-7x+82=33

-7x=33-82

-7x=-49 cut the negative signs as its LHS and RHS

x=49/7=7

b) - 5x+3 (3x-3) = 3 as y=3x-3 is given

-5x+9x-9=3

4x-9=3

4x=3+9

x=12/4=3

c) 4x+11-5x=9

-x+11=9

-x=9-11

-x=-2 cut the negative signs as its LHS and RHS

x=2

d) 5y + - 5-2y=-11 as x=-5-2y is given

3y+-5=-11

3y=-11+5

3y=-6

y=-6/3=-2

e) - 5x-4 (2x+1) = 35 as y=2x+1

-5x-8x+4=35

3x+4=35

3x=35-4

3x=31

x=31/3

x=10.3

Step-by-step explanation:

a) 3x+2 (41-5x) = 33 as y=41-5x is given

3x+82-10x=33

-7x+82=33

-7x=33-82

-7x=-49 cut the negative signs as its LHS and RHS

x=49/7=7

b) - 5x+3 (3x-3) = 3 as y=3x-3 is given

-5x+9x-9=3

4x-9=3

4x=3+9

x=12/4=3

c) 4x+11-5x=9

-x+11=9

-x=9-11

-x=-2 cut the negative signs as its LHS and RHS

x=2

d) 5y + - 5-2y=-11 as x=-5-2y is given

3y+-5=-11

3y=-11+5

3y=-6

y=-6/3=-2

e) - 5x-4 (2x+1) = 35 as y=2x+1

-5x-8x+4=35

3x+4=35

3x=35-4

3x=31

x=31/3

x=10.3