What's the equation of the line that passes through (-4,3) and is perpendicular to the line y=7/5x-3/5

A) 5x+7y=1

B) 7x+5y=-13

C) 7x+5y=-1

D) 3x+5y=7

Two lines perpendicular to each other having slopes m1 and m2 are related as:

m1 * m2=-1 ... (1)

First we find slope m1 of the line y=7/5x-3/5

comparing this equation with slope intercept form y=mx+b,

slope m1=7/5

NOw using rule (1) here to get value of m2

7/5 * m2 = -1

m2 = -5/7 ... (2)

Now the line passes through (-4,3) and has slope m2 = -5/7

we use slope intercept form to get the value of y intercept

y=mx+b

3 = (-5/7) (-4) + b

3=2.86 + b

b=0.14

At last we plug the value of b and m in slope intercept form to get the final equation as:

y = (-5/7) x + 0.14