What is the radius of the circle with this equation of (x-5) 2 + (y+7) 2=8

2√2

Step-by-step explanation:

compare this equation with the standard equation of a circle centered at (h, k) with radius r:

(x - h) ^2 + (y - k) ^2 = r^2

(x - 5) ^2 + (y + 7) ^2=8

Clearly, r^2 = (radius) ^2 = 8, and so the radius, r, is √8, or 2√2