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31 December, 20:10

4k+2/k2-4 • k-2/2k+1=

What is the numerator?

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Answers (1)
  1. 31 December, 20:31
    0
    (4k+2) (k-2) / (k^2-4) (2k+1)

    =2 (2k+1) (k-2) / (k^2-2^2) (2k+1)

    Cancel out 2k+1

    2 (k-2) / (k-2) (k+2) using a^2-b^2 = (a-b) (a+b)

    cancel out k-2

    2/k+2

    Therefore numerator is 2
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