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22 January, 23:26
What is the sum of the √-2 and √-18?
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Justus Griffin
23 January, 01:56
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The sum is 4 i√2
Step-by-step explanation:
Both the numbers √-2 and √-18 are imaginary number and thus can be presented as
i√2 and i√18
On simplifying, the i√18 can be written as i√ (9 x 2)
Taking out square root of 9 we get-
3i√2
Thus the summation of i√2 and i√18 can be written as
i√2 + 3i√2
= 4 i√2
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Gustavo Sheppard
23 January, 03:09
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The correct answer is (4 √2) i
Step-by-step explanation:
The sum we are looking is "x"
x = √-2 + √-18
By the Radical Properties of Multiplication,
x=√-2 + √ (-2*9)
x=√-2 + √-2 * √9
Considering √-2 = √ ((-1) * 2) = √-1 * √2
According to the propriety of complex numbers, we can say
i=√-1
Replacing
x = i √2 + 3 i√2
The answer is x = (4 √2) i
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