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4 March, 20:12

How many milliliters of a 12% alcohol solution and how many milliliters of a 30% alcohol solution must be mixed to obtain 72 ml of a 20% alcohol solution?

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  1. 4 March, 23:03
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    Target concentration = 20%.

    Ratio of 12% and 30% alcohols needed

    30-20 : 20-12 = 10:8 = 5:4

    Volume of 12% = 72 mL * (5 / (5+4)) = 40 mL

    Volume of 30% = 72 mL * (4 / (5+4)) = 32 mL

    Total = 40+32 = 72 mL of 20%
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