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2 August, 08:50

Given

/qquad / overline{OA}/perp/overline{OC}

OA



OC

start overline, O, A, end overline, / perp, start overline, O, C, end overline

/qquad m / angle BOC = 6x - 6^/circm∠BOC=6x-6



m, angle, B, O, C, equals, 6, x, minus, 6, degrees

/qquad m / angle AOB = 5x + 8^/circm∠AOB=5x+8



m, angle, A, O, B, equals, 5, x, plus, 8, degrees

Find m/angle BOCm∠BOCm, angle, B, O, C:

+4
Answers (1)
  1. 2 August, 09:19
    0
    It would be 2x over 6
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