What is the quotient of

y-5/sqrt{2y^2-7y-15}

A. 2y + 3

B. 2y - 3

C. 2y - 17y R - 70

D. 2y - 17y R 70

I think its A

None of these

Step-by-step explanation:

y-5/√ (2y2 - 7y - 15)

On simplifying 2y2 - 7y - 15, we get

2y2 - (10-3) y - 15

= 2y2 - 10y - 3y-15

= 2y (y-5) - 3 (y-5)

= (2y-3) (y-5)

On squaring nominator and denominator we get

(y-5) 2 / (2y-3) (y-5)

= (y-5) / (2y-3)

So the quotient becomes, 5/2

While the remainder becomes 2.5