If f (x) = 2x-5 and g (x) = x²+1, what is g (f (x))

I believe it would be 4x^2-20x+26

Step-by-step explanation:

Substitute the f (x) equation in where the x is in the g (x) equation, so ...

g (f (x)) = (2x-5) ^2+1 = (2x-5) (2x-5) + 1 = 4x^2-20x+26.

If you want, you could factor out a 2 also to get 2 (2^2-10x+13)