The center of a circle is at (-5 12) and it has a radius of 16. what is the equation of the circle?

(x+5) ^2 + (y-12) ^2=256

(x+5) ^2 + (y-12) ^2=4

(x-5) ^2 + (y+12) ^2=256

(x-5) ^2 + (y+12) ^2=4

(x+5) ^2 + (y-12) ^2=256

Step-by-step explanation:

Comparing the given (x+5) ^2 + (y-12) ^2=256

to (x - h) ^2 + (y - k) ^2 = r^2,

we see that h must be - 5, k must be 12 and r must be 16. This is the desired equation of the circle with center at (-5, 12) and radius 16.