Which is the same solution a x2-16x+12 = 0

An equation which has the same solution as the given equation is:

(x - 18) (x + 2) + 48 = 0 ...

Step-by-step explanation:

The given expression is:

x2-16x+12

Break the constant term:

x^2-16x-36 + 48=0

[x^2-16x-36] + 48=0

Now break the middle term inside the brackets

(x^2-18x+2x-36) + 48=0

Take the common

[x (x-18) + 2 (x-18) ]+48=0

(x-18) (x+2) + 48=0

Thus an equation which has the same solution as the given equation is:

(x - 18) (x + 2) + 48 = 0 ...