Brandon is thinking of a number that is divisible by 6 and 8. What is the smallest number that Brandon could think of

since

6 = 2 * 3 <-- - two factors

8 = 2 * 2 * 2 <-- - three factors

and since the "2" is there on each, then we can just use that instance of it once.

so instead of using 2 * 3 * 2 * 2 * 2, we'll use 2 * 3 * 2 * 2, and that is our LCD.

2 * 3 * 2 * 2 = 24.