What are the zeros of the function?

g (x) = x^3-x^2-12x

Select each correct answer.

A. - 4

B. - 3

C. 0

D. 3

E. 4

B. - 3

C. 0

E. 4

Step-by-step explanation:

g (x) = x^3-x^2-12x

Set this equal to zero

0=x^3-x^2-12x

Factor out an x

0=x (x^2-x-12)

Factor inside the parentheses.

What two numbers multiply to - 12 and add to - 1

-4*3 = - 12

-4+3 = - 1

0=x (x-4) (x+3)

Using the zero product property

x=0 x-4=0 x+3=0

x=0 x=4 x=-3