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28 January, 22:41

The equation 2x² + px - 6 = 0 has equal roots.

Find the value (s) of p as a surd in its simplest form.

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Answers (1)
  1. 29 January, 02:01
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    Hello from MrBillDoesMath!

    Answer:

    There is no p value that answers the question.

    Discussion:

    Consider the quadratic ax^2 + b^x + c = 0. The solution is

    x = (-b + / - sqrt (b^2-4ac)) / 2a

    If b^2-4ac is NOT zero then there are two values of x that solve the equation. In b^2-4ac = 0, then both roots are equal, so there is only one solution.

    Taking a = 2, b = p, and c = - 6, in the quadratic formula:

    b^2 - 4ac = 0 = > (again, = 0 for a single root)

    p^2 - 4 (2) (-6) = 0 = >

    p^2 + 48 = 0 = >

    which has no real solution as p^2 > = 0, so p^2 + 48 > = 48 which means that p^2 + 48 = 0 is not possible

    Regards,

    MrB
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