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10 April, 21:36

Solve this system of equations

-2x+5y+4z=-4

-5x-y+z=-1

2y+2z=-4

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Answers (1)
  1. 10 April, 23:00
    0
    x = - 1, y = 2 and z = - 4.

    Step-by-step explanation:

    -2x + 5y + 4z = - 4 ... (A)

    -5x - y + z = - 1 ... (B)

    2y + 2z = - 4 ... (C) Multiply (A) by 5 and (B) by - 2:

    -10x + 25y + 20z = - 20 ... (D)

    10x + 2y - 2z = 2 ... (E) Adding D + E:

    27y + 18z = - 18 Dividing by 9:

    3y + 2z = - 2 ... (F) Subtract: (C) - (F):

    -y = - 2

    y = 2.

    Substitute for y is (C):

    4 + 2z = - 4

    2z = - 8

    z = - 4.

    Substitute for y and z in (A):

    -2x + 5 (2) + 4 (-4) = - 4

    -2x = - 10 + 16 - 4 = 2

    x = - 1.
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