Manipulate the quadratic equation x² - 6 = 5x so the equation

equals 0, then factor the quadratic using the grouping method, and

find the zeros of the function.

A. X=1 and x=6

B. X=-1 and x=-6

C. X=-1 and x=6

D. X=1 and x=-6

Must show work.

X^2-6-5x=0

x^2-5x-6=0

x^2-6x+1x-6=0

x (x-6) + 1 (x-6) = 0

(x-6) (x+1) = 0

x-6=0

x=0+6

x=6

x+1=0

x=0-1

x=-1

Option C

answer B: x = - 1 and x = 6

Step-by-step explanation:

Rewrite x² - 6 = 5x as x² - 5x - 6 = 0, which is in standard form for a quadratic.

Factoring by grouping results in x^2 - 6x + 1x - 6. pr

x (x - 6) + 1 (x - 6) = 0.

This simplifies to (x - 6) (x + 1) = 0, whose solutions are x = 6 and x = - 1.

This corresponds to given answer B: x = - 1 and x = 6