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Mathematics
Karla Smith
26 July, 02:27
G (x) = (x^2+1) (3x-5) what is the value of g (4) ?
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Gustavo
26 July, 05:03
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g (x) = x^2 + 1 (3x - 5)
Replace all x's with 4.
g (4) = 4^2 + 1 (3 * 4 - 5)
g (4) = 16 + 1 (12 - 5)
g (4) = 17 (7)
g (4) = 119 (This is your answer.)
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