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1 October, 12:33

Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. what percentage of light was actually absorbed by the sample?

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  1. 1 October, 13:09
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    Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. This means that the remainder of the light was absorbed by the sample given in the question.

    Now, from the 100% light that has been incident on the sample, if 85% was transmitted, then the percentage of light was actually absorbed by the sample can be found out as:

    percentage of light was actually absorbed by the sample=100% - (percentage of light transmitted by the sample)

    Therefore, percentage of light was actually absorbed by the sample=100%-85%=15%

    Thus, 15% light was actually absorbed by the sample.
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