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3 January, 17:56

Find three consecutive intergers such that three times the third is 102 more than the sum of the first and second.

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  1. 3 January, 19:36
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    A) x + x+1 + x+2

    We don't need equation A)

    B) 3 * (x+2) = (x + X+1) + 102

    3x + 6 = 2x + 1 + 102

    x = 97

    Numbers are 97, 98 and 99
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