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22 February, 17:08

The sum of three numbers is 98. The first number is 7 less than the second. The third number is 3 times the second. What are the numbers?

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  1. 22 February, 18:58
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    14, 21, and 63

    Step-by-step explanation:

    we can set the three unknown numbers as x, y, and z

    so

    x + y + z = 98

    now we are given that the first (x) is seven less than the second (y)

    x = y - 7

    the third number (z) is three times the second (y)

    z = 3y

    since we have an equation for z and x in terms of y, we can plug it into the first equation and solve for y.

    (y-7) + y + (3y) = 98

    y - 7 + y + 3y = 98

    y + y + 3y = 105

    5y = 105

    y=21

    now that we know y, we can plug its value into either the second or the third equation to find x or z (I chose to find z first)

    z = 3y

    z = 3 (21)

    z = 63

    now we can plug in y to find x

    x = y - 7

    x = 21 - 7

    x = 14

    so the three numbers should be 14, 21, and 63
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