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7 February, 20:20

Mr. Rich had 2 times more cars than motorcycles in his garage. After he bought 1 more car and sold 2 motorcycles, there were 3 times more cars than motorcycles. How many cars and motorcycles were there in garage?

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  1. 7 February, 21:00
    0
    In the Garage, Numeber of cars are 15 and Number of motorcycles are 5

    Step-by-step explanation:

    let number of motorcycles be = x

    he had 2 times more cars than motorcycles so, no of cars = 2x

    he bought 1 more car, so number of cars = 2x+1

    he sold 2 motorcycles, so motorcycles = x-2

    he had 3 times more cars than motorcycles so, we equate it like this:

    3 (x-2) = 2x+1

    solving the equation

    3x-6 = 2x+1

    here we find, x=7

    solving for no of cars:

    2x+1

    2 (7) + 1

    no of cars = 15

    solving for no of motorcycles:

    x-2

    7-2

    no of motorcycles = 5
  2. 7 February, 21:03
    0
    After the sale there were 15 cars and 5 motorcycles

    Step-by-step explanation:

    c=cars originally

    m=motorcycles originally

    c=2m (2 times the cars than motorcycles)

    (c+1) bought 1 car after sale

    sold 1 motor cycle (m-2) after sale

    (c+1) = 3 (m-2) (3 times more cars than motorcycles)

    (c+1) = 3 (m-2)

    distribute

    c+1 = 3m-6

    substitute c = 2m

    2m + 1 = 3m-6

    subtract 2m from each side

    2m+1-2m = 3m-6-2m

    1 = m-6

    add 6 to each side

    1+6 = m-6+6

    m=7

    c = 2m

    c = 2 (7) = 14

    c=14

    Originally there were 7 motorcycles and 14 cars

    After the sale c+1 = 15, m-2 = 5

    there were 15 cars and 5 motorcycles
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