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10 December, 21:58

complete the square to rewrite y=x^2-6x+16 in vertex form. Then state weather the vertex is a minimum and give its coordinates

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Answers (2)
  1. 10 December, 22:32
    0
    y = (x - 3) ² + 7 is a minimum vertex at (3, 7)

    Step-by-step explanation:

    the equation of a parabola in vertex form is

    y = a (x - h) ² + k

    where (h, k) are the coordinates of the vertex and a is a multiplier

    To obtain this form using completing the square

    • add / subtract (half the coefficient of the x-term) ² to x² - 6x

    y = x² + 2 ( - 3) x + 9 - 9 + 16 = (x - 3) ² + 7 ← in vertex form

    with vertex = (3, 7)

    Since coefficient of x² term > 0 then minimum
  2. 11 December, 01:29
    0
    minimum vertex at (3, 7)
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