What is the restriction of x^2-6x+5/x^2-3x-10

x ≠ - 2, 5

Step-by-step explanation:

The restrictions occur in the denominator which cannot be zero as this would make the function undefined. Equating the denominator to zero and solving gives the values that x cannot be.

solve x² - 3x - 10 = 0 ⇒ (x - 5 (x + 2) = 0 ⇒ x = - 2, 5