Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third

3, 5, 7

Step-by-step explanation:

1st number: (2k+1)

2nd number: (2k+3)

3rd number: (2k+5), k∈Z

3*[ (2k+1) + (2k+3) ] = 3 + 3 * (2k+5)

3 * (4k+4) = 3+6k+15

12k+12=18+6k

6k=6

k=1

1st number: (2k+1) = 3

2nd number: (2k+3) = 5

3rd number: (2k+5) = 7