Y = x^2 - 2x; domain {-3, 0, 5}

Question

Mathematics

Maren Haynes

25 April, 02:03

Y = x^2 - 2x; domain {-3, 0, 5}

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Answers (1)

Know the Answer?

Marina Gentry · Answer 1

range:{0,15}

Step-by-step explanation:

y=x²-2x

domain:{-3,0,5}

for range

when x=-3

y = (-3) ²-2 * (-3) = 9+6=15

when x=0

y=0-0=0

when x=5

y=5²-2*5=25-10=15

range:{0,15}

or

y=x²-2x+1-1 = (x-1) ²-1

when x=-3

y = (-3-1) ²-1=16-1=15

when x=0

y = (0-1) ²-1=1-1=0

when x=5

y = (5-1) ²-1=16-1=15