No. of diners = 240 Portions of juice served = 4 oz. per diner Size of juice can = 48 oz. How many cases of juice required if there are 8 cans in a case and you must buy a whole case?

Question

Mathematics

Nehemiah Rowe

7 August, 16:00

No. of diners = 240 Portions of juice served = 4 oz. per diner Size of juice can = 48 oz. How many cases of juice required if there are 8 cans in a case and you must buy a whole case?

+2

Answers (2)

Know the Answer?

Francis Vega · Answer 1

1 portion = 4oz

1 can = 48oz

1 can = 12 portion

240 portions : 12 portions = 20

1 case 8 cans

answer = 2 cases

Honey · Answer 2

2.5

Step-by-step explanation:

Multiply 240 by size of individual portion (4 oz.) = 960

Divide answer by standard can capacity (48oz.) = 20

Divide the resulting number of cans needed by the number of cans in a case to obtain the number of cases. (20 / 8) = 2.5