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15 February, 22:19

What is the greatest positive three-digit integer that is divisible by 5, 7 and 9?

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Answers (2)
  1. 15 February, 23:23
    0
    First, we want to see what the product of the three numbers is:

    9 * 7 * 5 = 315

    From there, we can find multiples of 315 to get the largest 3 - digit number divisible by 9, 7, and 5.

    315, 630, 945, 1260 ...

    The largest is 945.
  2. 15 February, 23:57
    0
    Find LCM:

    5 = 5

    7 = 7

    9 = 3²

    LCM = 3² x 5 x 7 = 315

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    Greatest 3-digit number:

    Greatest 3-digit number = 999

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    Find greatest 3-digit number divisible by 315:

    999 : 315 = 3 remainder 54

    Greatest 3-digit number divisible by 315 = 315 x 3 = 945.

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    Answer: 945
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