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4 December, 14:37

Determine whether the vectors (2, 3, l), (2, - 5, - 3), (-3, 8, - 5) are linearly dependent or linear independent. If the vectors are linearly dependent, express one as a linear combination of the others. (Solutions of homogeneous differential equations form a vector space: it is necessary to confirm whether given functions/vectors are linearly dependent or linearly independent, chapter 4).

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  1. 4 December, 17:17
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    So the vectors are linearly independent.

    Step-by-step explanation:

    So if they are linearly independent then the following scalars in will have the condition a=b=c=0:

    a (2,3,1) + b (2,-5,-3) + c (-3,8,-5) = (0,0,0).

    We have three equations:

    2a+2b-3c=0

    3a-5b+8c=0

    1a-3b-5c=0

    Multiply last equation by - 2:

    2a+2b-3c=0

    3a-5b+8c=0

    -2a+6b+10c=0

    Add equation 1 and 3:

    0a+8b+7c=0

    3a-5b+8c=0

    -2a+6b+10c=0

    Divide equation 3 by 2:

    0a+8b+7c=0

    3a-5b+8c=0

    -a+3b+2c=0

    Multiply equation 3 by 3:

    0a+8b+7c=0

    3a-5b+8c=0

    -3a+9b+6c=0

    Add equation 2 and 3:

    0a+8b+7c=0

    3a-5b+8c=0

    0a+4b+13c=0

    Multiply equation 3 by - 2:

    0a+8b+7c=0

    3a-5b+8c=0

    0a-8b-26c=0

    Add equation 1 and 3:

    0a+0b-19c=0

    3a-5b+8c=0

    0a-8b-26c=0

    The first equation tells us - 19c=0 which implies c=0.

    If c=0 we have from the second and third equation:

    3a-5b=0

    0a-8b=0

    0a-8b=0

    0-8b=0

    -8b=0 implies b=0

    We have b=0 and c=0.

    So what is a?

    3a-5b=0 where b=0

    3a-5 (0) = 0

    3a-0=0

    3a=0 implies a=0

    So we have a=b=c=0.

    So the vectors are linearly independent.
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