Find the perimeter of a square with an area of 702.25

area of a square = 702.25

A = side square

let's take side of a square = a

therefore,

702.25 = a^2

a = √702.25 = 26.5

perimeter (P) of a square = 4a

P = 4x 26.5 = 106

so perimeter of a square is 106