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5 September, 00:34

Which pair of complex factors results in a real number product? 15 (-15i) 3i (1 - 3i) (8 + 20i) (-8 - 20i) (4 + 7i) (4 - 7i)

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  1. 5 September, 00:46
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    D. (4+7i) (4-7i)
  2. 5 September, 04:20
    0
    (4 + 7i) (4 - 7i)

    Step-by-step explanation:

    This pair will produce a real answer because they are complex conjugates.

    Complex conjugates (a+bi) (a-bi) when multiplied together form a real number (a^2 + b^2)
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