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1 May, 01:03

6. The temperature of an iron block decreases from 85°C to 25°C. If the mass for

the block is 1.2 kg, calculate the heat lost by the block. (Citon = 0.115 cal/g.°C)

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  1. 1 May, 01:09
    0
    8280 cal

    Step-by-step explanation:

    Q=mc (delta) T

    Q=1200 (0.115) (-60)

    Q=8280 cal

    I used 1200 g instead of 1.2 kg
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