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Yesterday, 01:59

in a sample of 10 cards, 4 are red and 6 are blue. if 2 cards are selected at random from the sample, one at a time without replacement, what is the probability that both cards are not blue?

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  1. Yesterday, 02:06
    0
    It May Be ... Likely
  2. Yesterday, 03:41
    0
    If we want to find the probability that both cards are NOT blue, then we are basically finding the probability that both cards are red:

    4/10 * 3/9 = 2/15

    We did 3/9 because we already took away one red, which we did not replace.

    So, the answer is 2/15.
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