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11 October, 05:17

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 5% vinegar, and the second brand contains 15% vinegar. The chef wants to make 240 milliliters of a dressing that is 8% vinegar. How much of each brand should she use?

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Answers (2)
  1. 11 October, 06:44
    0
    168 ml of 5%,

    72 ml of 15%

    Step-by-step explanation:

    X + Y = 240

    X = 240 - Y

    0.05X + 0.15Y = 0.08 (240)

    0.05X + 0.15Y = 19.2

    X + 3Y = 384

    240 - Y + 3Y = 384

    2Y = 144

    Y = 72

    X = 240 - 72

    X = 168
  2. 11 October, 07:20
    0
    You want to setup an equation that will match the word problem. Let's call the amount of the first brand, F and the amount of the second brand, S.

    We want the total mixture to be 310mL so: F + S = 310

    Also, you want the total mixture to contain 8% vinegar so:.06F +.11S =.08 (310)

    Now, we can solve the system of equations using substitution.

    F + S = 310

    .06F +.11S =.08 (310)

    F = 310 - S [solve 1st equation for F]

    .06 (310 - S) +.11S =.08 (310) [substitute into 2nd equation]

    18.6 -.06S +.11S = 24.8

    .05S = 6.2

    S = 124

    F + 124 = 310 [substitute answer for S back into original equation]

    F = 186

    Answer: to make a 310mL mixture that contains 8% vinegar, use 186mL of the first brand and 124mL of the second brand.
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