What is the factored form of the expression over the complex numbers? 121x^2+36y^2

(11x-6iy) (11x-6iy)

(11x+6y) (11x-6y)

(11x+6iy) (11x-6iy)

(11x+6iy) (11x+6iy)

(11x + 6y) (11x - 6y)

This is my answer

It's the third answer. This is because since there is no middle term where both variables are combined, that would lead to the signs of the 2 factors to be different. However, that still leaves 2 answers, 3 and 2. If we were to square i, you would get - 1. This is because √-1 is equal to i. i^2 would be - 1. Since the sign in the unfactored expression is positive and not negative, that would mean that the i in the factoring turned it around. that leads us to believe that answer 3 is the correct answer.