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19 May, 05:46

Find 3 consecutive odd integers such that the sum of the smallest number and the middle number is 27 less than 3 times the largest number

Answers (1)
  1. M
    19 May, 05:53
    0
    Let consecutive odd numbers be

    x, x+2, x+4

    Smallest number = x

    Middle number = x+2

    Largest number = x+4

    According to condition (x) + (x+2) - 27 = 3 (x+4)

    x+x+2-27 = 3 (x+4)

    2x-25 = 3x+12

    Subtracting 2x and 12 both sides

    2x-25-2x-12=3x+12-2x-12

    -37 = x this is smallest odd number.

    Other two odd numbers are (x+2) = (-37+2) = (-35)

    & (x+4) = (-37+4) = (-33)

    so three consecutive odd numbers are - 37,-35, - 33
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