if there is a 10% chance of sun tomorrow and 20% chance of wind and no sun what is the probability that it is windy given that it is not sunny? round your answer to the nearest percent

=22%

Step-by-step explanation:

Since we have given two conditions simultaneously that is windy and not sunny. So we will use the concept of conditional probability.

The probability of sunny day = P (sunny) = 10%

P (sunny) = 10%=0.1

The probability of windy and not sunny=P (windy|not sun) = 20%

P (windy|not sun) = 20% = 0.2

Now divide the both probabilities:

P (windy|not sun) / P (sunny)

=0.2/[1-0.1]

{Hence there are 10% chances of sun tomorrow than there are (1 - 0.1) chances of no sun}

If we subtract 1 from 0.1 than it becomes:

=0.2/0.9

=2/9

=0.2222222222

=22%

Hence the probability that it is windy = 22% ...