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13 September, 08:52

Find y when x=14 if y directly with x2, and y = 72 x = 6

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  1. 13 September, 09:54
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    If y varies directly with x^2

    Let y=mx^2 where m is constant

    When x=6, y=72, thus value of m = (y/x^2) = 72/36=2

    Thus equation becomes y = 2 (x^2)

    Keeping x=14,

    y==2 (14^2) = = 392
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